Y=11x^2-396

Solution for Y=11x^2-396 equation:

=11Y^2-396

We move all terms to the left:

-(11Y^2-396)=0

We get rid of parentheses

-11Y^2+396=0

a = -11; b = 0; c = +396;
Δ = b2-4ac
Δ = 02-4·(-11)·396
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-132}{2*-11}=\frac{-132}{-22}
=+6
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+132}{2*-11}=\frac{132}{-22}
=-6
$